3x-0.01x^2-200=0

Solution for 3x-0.01x^2-200=0 equation:

3x-0.01x^2-200=0

a = -0.01; b = 3; c = -200;
Δ = b2-4ac
Δ = 32-4·(-0.01)·(-200)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-1}{2*-0.01}=\frac{-4}{-0.02}
=+200
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+1}{2*-0.01}=\frac{-2}{-0.02}
=+100
$